Asked by Name
Calculate the rates of change in first flowering dates per degree Celsius for the average species, the highbush blueberry, and the yellow wood sorrel, between 1852 and 2006. Round your answers to one decimal point.
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Answered by
GPT-5 mini
AI
I don’t have the data values from your source (the 1852 and 2006 flowering dates and the temperature change), so I can’t compute the numeric answers yet. Provide either
- the first-flowering dates in 1852 and 2006 for (a) the average species, (b) highbush blueberry, and (c) yellow wood sorrel, plus the temperature in 1852 and 2006 (or the temperature change), or
- a photo/screenshot of the figure/table you’re using.
How to calculate once you have the numbers
1. Compute the change in flowering date (in days): Δdays = date2006 − date1852. (If flowering happens earlier in 2006, Δdays will be negative.)
2. Compute the temperature change (in °C): ΔT = T2006 − T1852.
3. Rate (days per °C) = Δdays / ΔT.
4. Round the result to one decimal place. A negative rate means flowering is earlier per °C of warming.
Example (illustration only)
- If average species: date1852 = day 150, date2006 = day 140 → Δdays = −10 days.
- If ΔT = +0.9 °C → rate = −10 / 0.9 = −11.111… → rounded = −11.1 days/°C.
Send the numbers or the image and I’ll compute the three rates and round them to one decimal place.
- the first-flowering dates in 1852 and 2006 for (a) the average species, (b) highbush blueberry, and (c) yellow wood sorrel, plus the temperature in 1852 and 2006 (or the temperature change), or
- a photo/screenshot of the figure/table you’re using.
How to calculate once you have the numbers
1. Compute the change in flowering date (in days): Δdays = date2006 − date1852. (If flowering happens earlier in 2006, Δdays will be negative.)
2. Compute the temperature change (in °C): ΔT = T2006 − T1852.
3. Rate (days per °C) = Δdays / ΔT.
4. Round the result to one decimal place. A negative rate means flowering is earlier per °C of warming.
Example (illustration only)
- If average species: date1852 = day 150, date2006 = day 140 → Δdays = −10 days.
- If ΔT = +0.9 °C → rate = −10 / 0.9 = −11.111… → rounded = −11.1 days/°C.
Send the numbers or the image and I’ll compute the three rates and round them to one decimal place.
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