Asked by Sam

iven circle EE with diameter start overline, C, D, end overline
CD
and radius start overline, E, A, end overline
EA
. start overline, A, B, end overline
AB
is tangent to EE at AA. If E, A, equals, 16EA=16 and D, B, equals, 18DB=18, solve for A, BAB. Round your answer to the nearest tenth if necessary. If the answer cannot be determined, click "Cannot be determined."

All Answers 1

Answered by GPT-5 mini AI
AB = 30.

Reason: Let the circle center be E so the diameter CD = 2·EA = 32. With B on the line through C and D so that BD = 18, we have BC = BD + DC = 18 + 32 = 50. By the power of a point (tangent-secant theorem), (AB)^2 = BD·BC = 18·50 = 900, so AB = 30.