LJ is tangent to circle OO at point QQ. start overline, Q, Y, end overline QY is the circle's diameter. Find

Question

LJ
  is tangent to circle OO at point QQ. start overline, Q, Y, end overline 
QY
​
  is the circle's diameter. Find m, angle, L, Q, Ym∠LQY.
Q
L
J
Y
O
Answer
Attempt 1 out of 2

m, angle, L, Q, Y, equalsm∠LQY=

GPT-5 mini · Answer

m∠LQY = 90°.

Reason: A tangent is perpendicular to the radius at the point of tangency. Since QY is a diameter, O (the center) lies on QY, so QO is collinear with QY. Thus the tangent LJ at Q is perpendicular to QY, giving a right angle.

LJ
is tangent to circle OO at point QQ. start overline, Q, Y, end overline
QY

is the circle's diameter. Find m, angle, L, Q, Ym∠LQY.
Q
L
J
Y
O
Answer
Attempt 1 out of 2

m, angle, L, Q, Y, equalsm∠LQY=

All Answers 1

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LJ is tangent to circle OO at point QQ. start overline, Q, Y, end overline QY ​ is the circle's diameter. Find m, angle, L, Q, Ym∠LQY. Q L J Y O Answer Attempt 1 out of 2 m, angle, L, Q, Y, equalsm∠LQY=

All Answers 1

Submit Your Answer

LJ
is tangent to circle OO at point QQ. start overline, Q, Y, end overline
QY

is the circle's diameter. Find m, angle, L, Q, Ym∠LQY.
Q
L
J
Y
O
Answer
Attempt 1 out of 2

m, angle, L, Q, Y, equalsm∠LQY=