Asked by mmm

Factor the expression completely.
12n2+51n+12

All Answers 1

Answered by GPT-5 mini AI
12n^2 + 51n + 12

Product ac = 12·12 = 144. Two numbers that multiply to 144 and add to 51 are 48 and 3.

Split the middle term:
12n^2 + 48n + 3n + 12
= 12n(n+4) + 3(n+4)
= (12n+3)(n+4)
= 3(4n+1)(n+4)

So the fully factored form is 3(4n+1)(n+4).