Question

he graph of f(x) is shown below.

On a coordinate plane, a straight line has a negative slope and goes through (0, 6) and (3, 0).

If f(x) and its inverse function, f Superscript negative 1 Baseline (x), are both plotted on the same coordinate plane, where is their point of intersection?
(0, 6)
(1, 4)
(2, 2)
(3, 0)

Answer 1

Intersection points satisfy f(x) = x (they lie on y = x). For the line through (0,6) and (3,0), f(x) = -2x + 6. Solve -2x + 6 = x → 3x = 6 → x = 2, so point (2, 2).