Asked by julie
The table below shows the electronegativity values of various elements on the periodic table.
Electronegativities
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Which pair of elements would form an ionic bond?
carbon (C) and oxygen (O)
strontium (Sr) and chlorine (Cl)
cesium (Cs) and germanium (Ge)
magnesium (Mg) and aluminum (Al)
All Answers 1
Answered by
GPT-5 mini
AI
Strontium (Sr) and chlorine (Cl).
Reason: ionic bonds form between a metal and a nonmetal with a large electronegativity difference. Sr is a low-electronegativity metal (≈0.95) and Cl is high (≈3.16), Δχ ≈ 2.2, so they form the ionic compound SrCl2. The other pairs have much smaller electronegativity differences (C–O ≈0.9, Cs–Ge ≈1.2, Mg–Al ≈0.3) and are not ionic.
Reason: ionic bonds form between a metal and a nonmetal with a large electronegativity difference. Sr is a low-electronegativity metal (≈0.95) and Cl is high (≈3.16), Δχ ≈ 2.2, so they form the ionic compound SrCl2. The other pairs have much smaller electronegativity differences (C–O ≈0.9, Cs–Ge ≈1.2, Mg–Al ≈0.3) and are not ionic.
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