Question

Use any method to locate the zeros of y=−3x^2+12x+15
.(1 point)
Responses

(0,15)

left parenthesis 0 comma 15 right parenthesis

There are no zeros.
There are no zeros.

(−1,0)(5,0)

left parenthesis negative 1 comma 0 right parenthesis left parenthesis 5 comma 0 right parenthesis

(1,0)(−5,0)

Answer 1

Solve -3x^2 + 12x + 15 = 0.

Divide by -3: x^2 - 4x - 5 = 0 → (x - 5)(x + 1) = 0.

Zeros: x = 5 and x = −1, i.e. points (5,0) and (−1,0).