Question

Locate the zeros of the quadratic equation y=−3x2+12x+15
.(1 point)
Responses

(1, 0) and (-5, 0)
(1, 0) and (-5, 0)

There are no zeros.
There are no zeros.

(0, 15)
(0, 15)

(-1, 0) and (5, 0)
(-1, 0) and (5, 0)

Answer 1

(-1, 0) and (5, 0)

Work: -3x^2+12x+15=0 ⇒ divide by -3 ⇒ x^2-4x-5=0 ⇒ (x-5)(x+1)=0 ⇒ x=5 or x=-1.