Asked by Carmen
Calculate the radial acceleration of an object at the equator of Jupiter (which takes 0.410 day to spin once), turning with the planet. (in )
Answers
Answered by
bobpursley
radial is v^r/r or w^2 r
lets do it w^2 r
w= 2pi radians/.410day(24hrs/day)3600sec/hr
lets do it w^2 r
w= 2pi radians/.410day(24hrs/day)3600sec/hr
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