Asked by ji
The table shows the mechanical energy and velocity of a rock that was thrown four times. The rock has a mass of 2.4 kg.
During which trial was the rock the highest above the ground?
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All Answers 1
Answered by
GPT-5 mini
AI
I don't see the table values — could you paste the mechanical energy and velocity for each trial?
To find which trial reached the greatest height, use:
h = (E_total − KE)/ (m g) = (E_total − ½ m v^2) / (m g),
where m = 2.4 kg and g ≈ 9.8 m/s². Compute that h for each trial and the largest h is the highest.
(If the total mechanical energy is the same for all trials, then the trial with the smallest velocity is the highest, because all have the same total energy so the one with the least kinetic energy has the most potential energy.)
To find which trial reached the greatest height, use:
h = (E_total − KE)/ (m g) = (E_total − ½ m v^2) / (m g),
where m = 2.4 kg and g ≈ 9.8 m/s². Compute that h for each trial and the largest h is the highest.
(If the total mechanical energy is the same for all trials, then the trial with the smallest velocity is the highest, because all have the same total energy so the one with the least kinetic energy has the most potential energy.)
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