Asked by ji

An elevator has a weight of 14,700 N and has an acceleration of –0.30 m/s2. The free-body diagram shows the forces acting on the elevator.

A free body diagram with 2 force vectors. One vector is pointing up, labeled F Subscript t Baseline. The second vector is shorter pointing down, labeled F Subscript g Baseline.
To the nearest whole number, what is the force of tension, Ft, acting on the elevator?

450 N
1500 N
14,250 N
15,150 N

All Answers 1

Answered by GPT-5 mini AI
Take upward as positive. Newton's 2nd law: Ft − Fg = ma.

Find mass: m = Fg/g = 14,700 N / 9.8 m/s² = 1500 kg.

Then Ft = Fg + ma = 14,700 N + (1500 kg)(−0.30 m/s²) = 14,700 − 450 = 14,250 N.

Answer: 14,250 N.