Question

Given circle EE with diameter start overline, C, D, end overline
CD
and radius start overline, E, A, end overline
EA
. start overline, A, B, end overline
AB
is tangent to EE at AA. If E, C, equals, 5EC=5 and E, A, equals, 5EA=5, solve for A, DAD. Round your answer to the nearest tenth if necessary. If the answer cannot be determined, click "Cannot be determined."

Answer 1

Interpret the requested angle as ∠CAD (the angle at A subtended by the diameter CD). Any angle inscribed in a semicircle is a right angle, so ∠CAD = 90°.

Rounded to the nearest tenth: 90.0°.