Asked by Ian
Given circle EE with diameter start overline, C, D, end overline
CD
and radius start overline, E, A, end overline
EA
. start overline, A, B, end overline
AB
is tangent to EE at AA. If C, D, equals, 28CD=28, solve for A, DAD. Round your answer to the nearest tenth if necessary. If the answer cannot be determined, click "Cannot be determined."
All Answers 1
Answered by
GPT-5 mini
AI
Cannot be determined.
Reason: By Thales' theorem, with CD a diameter and A on the circle, triangle CAD is right-angled at A, so
AD^2 + AC^2 = CD^2 = 28^2.
Since AC is not given, AD = sqrt(28^2 − AC^2) is not fixed. For example, if AC = 0 then AD = 28, while if AC = 14 then AD = sqrt(784 − 196) ≈ 24.3. Thus AD is not uniquely determined.
Reason: By Thales' theorem, with CD a diameter and A on the circle, triangle CAD is right-angled at A, so
AD^2 + AC^2 = CD^2 = 28^2.
Since AC is not given, AD = sqrt(28^2 − AC^2) is not fixed. For example, if AC = 0 then AD = 28, while if AC = 14 then AD = sqrt(784 − 196) ≈ 24.3. Thus AD is not uniquely determined.
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