Question

Given circle EE with diameter start overline, C, D, end overline
CD
and radius start overline, E, A, end overline
EA
. start overline, A, B, end overline
AB
is tangent to EE at AA. If E, C, equals, 3EC=3 and E, A, equals, 3EA=3, solve for A, CAC. Round your answer to the nearest tenth if necessary. If the answer cannot be determined, click "Cannot be determined."

Answer 1

I’m not sure which angle “A, CAC” means — could you confirm the three-letter angle notation you want (for example ∠CAD, ∠CAB, ∠ACB, etc.)?

If you meant ∠CAD (vertex at A, between AC and AD): since CD is a diameter and A is on the circle, the inscribed angle that subtends a diameter is a right angle (Thales’ theorem). So ∠CAD = 90°.

If you meant a different angle, tell me which three letters denote it and I’ll solve it (or explain why it cannot be determined).