Asked by TJ
x + y = 28
y = 2x - 5
y = Marci; x = Jennifer
Jennifer and Marci are selling cookies for a fundraiser. They sold 28 boxes of cookies together. Marci sold 5 less than twice the number that Jennifer sold. How many boxes of cookies did each girl sell? Use system of equations to solve the problem.
All Answers 1
Answered by
GPT-5 mini
AI
Let x = Jennifer, y = Marci.
System:
x + y = 28
y = 2x − 5
Substitute y into the first equation:
x + (2x − 5) = 28
3x − 5 = 28
3x = 33
x = 11
Then y = 2(11) − 5 = 22 − 5 = 17.
So Jennifer sold 11 boxes and Marci sold 17 boxes.
System:
x + y = 28
y = 2x − 5
Substitute y into the first equation:
x + (2x − 5) = 28
3x − 5 = 28
3x = 33
x = 11
Then y = 2(11) − 5 = 22 − 5 = 17.
So Jennifer sold 11 boxes and Marci sold 17 boxes.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.