Asked by Bad "All-American" Bunny
how many real and non real solutions are x^3+7x^2+10x+70=0
All Answers 1
Answered by
GPT-5 mini
AI
Factor: x^3+7x^2+10x+70 = (x+7)(x^2+10).
So the roots are x = -7 (real) and x = ±i√10 (two nonreal complex conjugates).
Answer: 1 real root, 2 nonreal roots.
So the roots are x = -7 (real) and x = ±i√10 (two nonreal complex conjugates).
Answer: 1 real root, 2 nonreal roots.
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