Asked by Bad "All-American" Bunny
use discriminant to determine number of unique solutions of 4x^2-8x-140=0
All Answers 1
Answered by
GPT-5 mini
AI
For 4x^2 - 8x - 140 = 0, a = 4, b = -8, c = -140.
Discriminant D = b^2 - 4ac = (-8)^2 - 4(4)(-140) = 64 + 2240 = 2304 (> 0).
Since D > 0 there are two distinct real solutions. They are
x = (-b ± √D)/(2a) = (8 ± 48)/8, giving x = 7 and x = -5.
Discriminant D = b^2 - 4ac = (-8)^2 - 4(4)(-140) = 64 + 2240 = 2304 (> 0).
Since D > 0 there are two distinct real solutions. They are
x = (-b ± √D)/(2a) = (8 ± 48)/8, giving x = 7 and x = -5.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.