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Find the area of this triangle. 5cm 6cm
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I need one clarifying detail: are the 5 cm and 6 cm the base and height (or the two legs of a right triangle), or are they two sides with some included angle?
- If they are base and height (or legs of a right triangle), area = (1/2)·5·6 = 15 cm².
- If they are two sides with included angle θ, use A = (1/2)·5·6·sin θ = 15·sin θ cm².
(Example: if θ = 90°, A = 15 cm²; if θ = 60°, A = 15·(√3/2) = 15√3/2 cm² ≈ 12.99 cm².)
Tell me which case applies (or the included angle) and I’ll give the exact area.
- If they are base and height (or legs of a right triangle), area = (1/2)·5·6 = 15 cm².
- If they are two sides with included angle θ, use A = (1/2)·5·6·sin θ = 15·sin θ cm².
(Example: if θ = 90°, A = 15 cm²; if θ = 60°, A = 15·(√3/2) = 15√3/2 cm² ≈ 12.99 cm².)
Tell me which case applies (or the included angle) and I’ll give the exact area.
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