Question

The manager of a fitness club wants to analyze the weekly exercise habits (in hours) of the members. He collects the following dataset: {2, 4, 5, 7, 8, 8, 9, 9, 10, 11, 12, 13, 14, 15, 15, 20}. Create a histogram beginning at 1, with a bin width of 3.

(1 point)
Looking at the histogram, we would expect the mean
the median because the shape of the histogram appears to be
.

Answer 1

Bins (start = 1, width = 3) and frequencies:
- [1,4): 1
- [4,7): 2
- [7,10): 5
- [10,13): 3
- [13,16): 4
- [16,19): 0
- [19,22): 1

(You can plot these as bars of heights 1,2,5,3,4,0,1.)

Mean = (sum) 162/16 = 10.125
Median = average of 8th and 9th values = (9 + 10)/2 = 9.5

Looking at the histogram, the mean is greater than the median because the distribution is right-skewed (positively skewed).