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Find the surface area of this pyramid. 5m 5m
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I need to be sure which two 5 m measurements you mean (base side, slant height, or vertical height?). Common interpretation: a regular square pyramid with base side s = 5 m and slant height l = 5 m. In that case:
Surface area = base area + lateral area
= s^2 + 4*(1/2 * s * l) = s^2 + 2 s l
= 5^2 + 2(5)(5) = 25 + 50 = 75 m^2.
If instead the pyramid has base side 5 m and vertical height h = 5 m, the slant height is l = sqrt((s/2)^2 + h^2) = sqrt(2.5^2 + 5^2) ≈ 5.590, so
SA = 25 + 2(5)(5.590) ≈ 80.9 m^2.
Tell me which measurements you have if you want a different case.
Surface area = base area + lateral area
= s^2 + 4*(1/2 * s * l) = s^2 + 2 s l
= 5^2 + 2(5)(5) = 25 + 50 = 75 m^2.
If instead the pyramid has base side 5 m and vertical height h = 5 m, the slant height is l = sqrt((s/2)^2 + h^2) = sqrt(2.5^2 + 5^2) ≈ 5.590, so
SA = 25 + 2(5)(5.590) ≈ 80.9 m^2.
Tell me which measurements you have if you want a different case.
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