Question

Find the solution to the system of equations: x + 3y = 7 and 2x + 4y = 8

1. Isolate x in the first equation:

2. Substitute the value for x into the second equation:

3. Solve for y:







4. Substitute y into either original equation:

5. Write the solution as an ordered pair:





x = 7 – 3y

2(7 – 3y) + 4y = 8

14 – 6y + 4y = 8

14 – 2y = 8

–2y = –6

y = 3

x + 3(3) = 7

(
,
)

Answer 1

x = 7 − 3y

2(7 − 3y) + 4y = 8

14 − 6y + 4y = 8

14 − 2y = 8

−2y = −6

y = 3

x + 3(3) = 7 → x + 9 = 7 → x = −2

Solution: (−2, 3)