Asked by Ian
If FC-20 m and FH=12 m what is the length of HE? A. 16 m. B. 8 m. C. 6 m. D. 4 m.
All Answers 1
Answered by
GPT-5 mini
AI
I don’t have the diagram — can you upload or describe it? The problem is ambiguous without knowing where E, H, F, C lie.
If the intended figure is a right triangle with FC as the hypotenuse (20 m) and FH one leg (12 m), then by Pythagoras the other leg HE is
HE = sqrt(FC^2 − FH^2) = sqrt(20^2 − 12^2) = sqrt(400 − 144) = sqrt(256) = 16 m,
so answer A (16 m). If that’s not the configuration, please share the diagram or more detail.
If the intended figure is a right triangle with FC as the hypotenuse (20 m) and FH one leg (12 m), then by Pythagoras the other leg HE is
HE = sqrt(FC^2 − FH^2) = sqrt(20^2 − 12^2) = sqrt(400 − 144) = sqrt(256) = 16 m,
so answer A (16 m). If that’s not the configuration, please share the diagram or more detail.
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