Question

What is the surface area of the three-dimensional figure represented by this net?
it is a squre pyramid withthe four lengths being 3 and the height 8

Answer 1

Assuming the square base has side length 3 and the pyramid's vertical height is 8:

- Base area = 3^2 = 9.
- Slant height l = sqrt(8^2 + (3/2)^2) = sqrt(64 + 2.25) = sqrt(66.25) = (sqrt 265)/2.
- Area of one triangular face = (1/2)(3)l = (3/2)l = (3 sqrt 265)/4.
- Four triangular faces total = 4 * (3 sqrt 265)/4 = 3 sqrt 265.

Total surface area = 9 + 3 sqrt 265 ≈ 57.84 square units.