Question

Which of the following figures have an area of 64 square feet? Select THREE that apply.
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A.

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B.

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C.

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D.

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E.

Answer 1

I can't see the figures you mean — the message only shows the answer letters. Please either upload the image of the five figures or describe each figure and its labeled dimensions.

Meanwhile, here are quick checks you can use to decide which figures have area = 64 ft²:

- Square: area = side². So a square with side 8 ft has area 64 ft².
- Rectangle/parallelogram: area = base × height. Any rectangle with base × height = 64 (examples: 1×64, 2×32, 4×16, 8×8, 16×4) has area 64.
- Triangle: area = (1/2)·base·height. So you need base·height = 128 (examples: base 16 ft & height 8 ft, or 32 & 4).
- Circle: area = πr². Solve r = sqrt(64/π) ≈ 4.5135 ft. So a circle with that radius (or diameter ≈ 9.027 ft) has area 64.
- Semicircle: area = (1/2)πr² = 64 ⇒ r = sqrt(128/π) ≈ 6.385 ft.
- Trapezoid: area = ((b1 + b2)/2)·h. Solve ((b1 + b2)/2)·h = 64 for the given numbers.

If you post the figures or give the dimensions shown on each, I’ll compute each area and mark the three correct choices.