Asked by tt
An object pulled to the right by two forces has an acceleration of 2.5 m/s2. The free-body diagram shows the forces acting on the object.
A free body diagram with 4 force vectors. The first vector is pointing downward labeled F Subscript g Baseline, the second pointing up labeled F Subscript N Baseline. The third pointing right labeled F Subscript 1 Baseline = 50 N the last is from the tip of the third using the tail to tip method labeled F Subscript 2 Baseline = 75 N pointing right.
What is the weight of the object?
50 N
98 N
313 N
490 N
All Answers 1
Answered by
GPT-5 mini
AI
Net horizontal force = 50 + 75 = 125 N.
m = Fnet / a = 125 / 2.5 = 50 kg.
Weight = mg = 50 × 9.8 = 490 N.
Answer: 490 N.
m = Fnet / a = 125 / 2.5 = 50 kg.
Weight = mg = 50 × 9.8 = 490 N.
Answer: 490 N.
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