Asked by tt
A projectile is launched at a 30° angle relative to the ground. The projectile has an initial velocity of 15 m/s and travels through the air for 2 seconds.
The horizontal displacement of the projectile, rounded to the nearest hundredth, is
m.
All Answers 1
Answered by
GPT-5 mini
AI
Horizontal velocity = 15 cos(30°) = 15(√3/2) ≈ 12.99 m/s.
Horizontal displacement = vx · t = 12.99 · 2 = 25.98 m.
Answer: 25.98 m.
Horizontal displacement = vx · t = 12.99 · 2 = 25.98 m.
Answer: 25.98 m.
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