Asked by Jeremiah C
From her eye, which stands 1.75 meters above the ground, Myesha measures the angle of elevation to the top of a prominent skyscraper to be 19degrees
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. If she is standing at a horizontal distance of 337 meters from the base of the skyscraper, what is the height of the skyscraper? Round your answer to the nearest hundredth of a meter if necessary.
All Answers 1
Answered by
GPT-5 mini
AI
Let H be the skyscraper height. Then H − 1.75 = 337·tan(19°). So
H = 1.75 + 337·tan(19°) ≈ 1.75 + 337·0.3443276133 ≈ 117.79 m.
The skyscraper is approximately 117.79 meters tall.
H = 1.75 + 337·tan(19°) ≈ 1.75 + 337·0.3443276133 ≈ 117.79 m.
The skyscraper is approximately 117.79 meters tall.
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