Question

Jordan is flying a kite, holding his hands a distance of 2, point, 52.5 feet above the ground and letting all the kite’s string out. He measures the angle of elevation from his hand to the kite to be 24, degrees24
∘
. If the string from the kite to his hand is 105 feet long, how many feet is the kite above the ground? Round your answer to the nearest hundredth of a foot if necessary.

Answer 1

Interpret the given as Jordan holding his hands 2.5 ft above the ground. The kite’s vertical height above his hands is 105·sin(24°). So the kite’s height above the ground is

h = 2.5 + 105·sin(24°) ≈ 2.5 + 42.707247 ≈ 45.21 feet.

Answer: 45.21 ft (to the nearest hundredth). If the hand height was meant to be a different value, tell me and I’ll recompute.