Question

y = 0.124433(98) − 8.12906 = 12.194434 − 8.12906 = 4.065374y = 4.07.
What is the correlation coefficient for your data? (You may round to the nearest hundredth

Answer 1

I can’t compute the correlation coefficient from only the one evaluation you showed (y = 0.124433·98 − 8.12906 ≈ 4.07). I need either the original data points or a regression summary (R^2 or the standard deviations of x and y plus the slope).

Ways you can get r (round to nearest hundredth):

- If you have R^2 (coefficient of determination): r = ±√(R^2). Use the sign of the slope to choose + or − (here slope = +0.124433, so r would be positive).
- If you have slope b and sample standard deviations Sx and Sy: r = b · (Sx / Sy).
- If you have the raw data (xi, yi): compute Pearson’s r directly
r = [n·Σ(xy) − Σx·Σy] / sqrt([n·Σ(x^2) − (Σx)^2]·[n·Σ(y^2) − (Σy)^2]).
- In Excel/Google Sheets: =CORREL(x_range,y_range). On a calculator use the linear-regression function which usually also returns r.

If you paste the dataset or tell me R^2 (or Sx and Sy), I’ll compute r and round it to the nearest hundredth.