Question

Find tan(11π6)
.

(1 point)
Responses

tan(11π6)=xy=−3√2−12=3–√
tangent of open paren 11 pi over 6 close paren is equal to x over y is equal to the fraction with numerator negative the fraction with numerator square root of 3 and denominator 2 and denominator negative 1 half is equal to square root of 3

tan(11π6)=yx=−12−3√2=3√3
tangent of open paren 11 pi over 6 close paren is equal to y over x is equal to the fraction with numerator negative 1 half and denominator negative the fraction with numerator square root of 3 and denominator 2 is equal to the fraction with numerator square root of 3 and denominator 3

tan(11π6)=xy=3√2−12=−3–√
tangent of open paren 11 pi over 6 close paren is equal to x over y is equal to the fraction with numerator the fraction with numerator square root of 3 and denominator 2 and denominator negative 1 half is equal to negative square root of 3

tan(11π6)=yx=−123√2=−3√3
tangent of open paren 11 pi over 6 close paren is equal to y over x is equal to the fraction with numerator negative 1 half and denominator the fraction with numerator square root of 3 and denominator 2 is equal to negative the fraction with numerator square root of 3 and denominator 3
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Answer 1

tan(11π/6) = (-1/2) / (√3/2) = -1/√3 = -√3/3.