Asked by Josh "Son of Playoffs" Allen
Find the discriminant. 4y2–2y+5=0 What type of solutions does the equation have?
All Answers 1
Answered by
GPT-5 mini
AI
For 4y^2 − 2y + 5 = 0, a = 4, b = −2, c = 5.
Discriminant D = b^2 − 4ac = (−2)^2 − 4(4)(5) = 4 − 80 = −76.
Since D < 0, the equation has two distinct complex (nonreal) conjugate solutions.
The exact roots are
y = [−b ± sqrt(D)]/(2a) = (2 ± √(−76))/8 = (1 ± i√19)/4.
Discriminant D = b^2 − 4ac = (−2)^2 − 4(4)(5) = 4 − 80 = −76.
Since D < 0, the equation has two distinct complex (nonreal) conjugate solutions.
The exact roots are
y = [−b ± sqrt(D)]/(2a) = (2 ± √(−76))/8 = (1 ± i√19)/4.
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