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What is the molecular mass of gold, Au?
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What is the molecular mass of gold, Au?
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Question at position 11
What is the molecular mass of ammonium phosphate, (NH4)3PO4? Round your answer to the second decimal place.
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What is the molecular mass of ammonium phosphate, (NH4)3PO4? Round your answer to the second decimal place.
Question at position 12
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Question at position 12
What is the molecular mass of lead(II) nitrate, Pb(NO3)2? Round your answer to the second decimal place.
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What is the molecular mass of lead(II) nitrate, Pb(NO3)2? Round your answer to the second decimal place.
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Question at position 13
What is the molecular mass of sucrose, C12H22O11?
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All Answers 1
Answered by
GPT-5 mini
AI
I'll state the atomic masses used (common tabulated values) and show the calculations.
Atomic weights used: H = 1.008, C = 12.01, N = 14.01, O = 16.00, P = 30.97, Pb = 207.2, Au = 196.97 (all in g·mol⁻¹).
1) Gold, Au (atomic mass): 196.97 g·mol⁻¹
2) Ammonium phosphate, (NH4)3PO4:
- NH4 = 14.01 + 4(1.008) = 18.042 → 3 × 18.042 = 54.126
- PO4 = 30.97 + 4(16.00) = 94.97
- Total = 54.126 + 94.97 = 149.096 → 149.10 g·mol⁻¹ (rounded to 2 d.p.)
3) Lead(II) nitrate, Pb(NO3)2:
- NO3 = 14.01 + 3(16.00) = 62.01 → 2 × 62.01 = 124.02
- Pb = 207.2
- Total = 207.2 + 124.02 = 331.22 g·mol⁻¹ (to 2 d.p.)
4) Sucrose, C12H22O11:
- C12 = 12 × 12.01 = 144.12
- H22 = 22 × 1.008 = 22.176
- O11 = 11 × 16.00 = 176.00
- Total = 144.12 + 22.176 + 176.00 = 342.296 → 342.30 g·mol⁻¹
If you prefer I can recalc using more precise atomic weights (IUPAC standard values).
Atomic weights used: H = 1.008, C = 12.01, N = 14.01, O = 16.00, P = 30.97, Pb = 207.2, Au = 196.97 (all in g·mol⁻¹).
1) Gold, Au (atomic mass): 196.97 g·mol⁻¹
2) Ammonium phosphate, (NH4)3PO4:
- NH4 = 14.01 + 4(1.008) = 18.042 → 3 × 18.042 = 54.126
- PO4 = 30.97 + 4(16.00) = 94.97
- Total = 54.126 + 94.97 = 149.096 → 149.10 g·mol⁻¹ (rounded to 2 d.p.)
3) Lead(II) nitrate, Pb(NO3)2:
- NO3 = 14.01 + 3(16.00) = 62.01 → 2 × 62.01 = 124.02
- Pb = 207.2
- Total = 207.2 + 124.02 = 331.22 g·mol⁻¹ (to 2 d.p.)
4) Sucrose, C12H22O11:
- C12 = 12 × 12.01 = 144.12
- H22 = 22 × 1.008 = 22.176
- O11 = 11 × 16.00 = 176.00
- Total = 144.12 + 22.176 + 176.00 = 342.296 → 342.30 g·mol⁻¹
If you prefer I can recalc using more precise atomic weights (IUPAC standard values).
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