Question

The weight of a bucket is 186 N. The bucket is being raised by two ropes. The free-body diagram shows the forces acting on the bucket.

A free body diagram with 3 force vectors. The first vector is pointing downward, labeled F Subscript g Baseline = 186 N. The second vector is pointing up, labeled F Subscript 1 Baseline 105 N. The third vector is pointing upward from the tip of the second using the tail to tip method, labeled F Subscript 2 Baseline = 115 N. The combined two vectors pointing upward are shorter than the one pointing downward.

The acceleration of the bucket, to the nearest tenth, is
m/s2.

Answer 1

Sum the upward forces and subtract weight: Fnet = 105 + 115 − 186 = 34 N (upward).

Mass = 186 N / 9.8 m/s² = 19.0 kg (≈18.98 kg).

a = Fnet / m = 34 / 18.98 ≈ 1.8 m/s² upward.

So the acceleration is 1.8 m/s² (upward).