Question

A push lawnmower is shown, pointing left. A vector is pointing down to the left, parallel to the handle of the lawnmower, labeled F Subscript p Baseline = 70 N.
A boy is exerting a force of 70 N at a 50-degree angle on a lawn mower. He is accelerating at 1.8 m/s2. Round the answers to the nearest whole number.

What is the mass of the lawn mower?

kg

What is the normal force exerted on the lawn mower?

N

Answer 1

Horizontal component: F_x = 70 cos50° = 70(0.6428) ≈ 45.0 N.
Mass: m = F_x / a = 45.0 / 1.8 ≈ 25 kg.

Vertical component: F_y (down) = 70 sin50° = 70(0.7660) ≈ 53.6 N.
Normal force: N = mg + F_y = 25(9.8) + 53.6 ≈ 299 N.

Answers:
Mass = 25 kg
Normal force = 299 N