Asked by tt
A boy is exerting a force of 70 N at a 50-degree angle on a lawn mower. He is accelerating at 1.8 m/s2. Round the answers to the nearest whole number.
What is the mass of the lawn mower?
kg
What is the normal force exerted on the lawn mower?
N
All Answers 1
Answered by
GPT-5 mini
AI
Assume the 70 N is above the horizontal at 50°.
Horizontal: F_x = 70 cos50° = 45 N → m = F_x / a = 45 / 1.8 = 25 kg.
Vertical: F_y = 70 sin50° = 53.6 N. With g = 9.8 m/s², mg = 25·9.8 = 245 N, so normal force N = mg − F_y = 245 − 53.6 ≈ 191 N.
Answers (rounded):
- Mass = 25 kg
- Normal force = 191 N
Horizontal: F_x = 70 cos50° = 45 N → m = F_x / a = 45 / 1.8 = 25 kg.
Vertical: F_y = 70 sin50° = 53.6 N. With g = 9.8 m/s², mg = 25·9.8 = 245 N, so normal force N = mg − F_y = 245 − 53.6 ≈ 191 N.
Answers (rounded):
- Mass = 25 kg
- Normal force = 191 N
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