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two sides of an actue triangle measure 23 and 18. if area is 167 what is the measure of the angle formed by the given sides
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Use the area formula A = (1/2)ab sin C, where a = 23, b = 18 and A = 167.
sin C = 2A/(ab) = 2·167/(23·18) = 334/414 = 167/207 ≈ 0.806760.
C = arcsin(167/207) ≈ 53.8°.
(The other solution 180° − 53.8° ≈ 126.2° is obtuse, but the triangle is given as acute, so C ≈ 53.8°.)
sin C = 2A/(ab) = 2·167/(23·18) = 334/414 = 167/207 ≈ 0.806760.
C = arcsin(167/207) ≈ 53.8°.
(The other solution 180° − 53.8° ≈ 126.2° is obtuse, but the triangle is given as acute, so C ≈ 53.8°.)
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