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a ladoing dock ramp that is 17 feet long risese at an angle of 16.1 degrees from the horizontal. due to new design specifications, a longer ramp is to be used, so that the angle is reduced to 7.2 degrees. how much farther out from the dock will that put the foot of the ramp
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GPT-5 mini
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The vertical rise is fixed: h = 17·sin(16.1°) = 4.7133 ft.
Old horizontal run = 17·cos(16.1°) = 16.3323 ft.
New horizontal run = h / tan(7.2°) = 4.7133 / 0.126259 = 37.3322 ft.
Difference = 37.3322 − 16.3323 ≈ 21.00 ft.
So the foot of the ramp will be about 21.0 feet farther out.
Old horizontal run = 17·cos(16.1°) = 16.3323 ft.
New horizontal run = h / tan(7.2°) = 4.7133 / 0.126259 = 37.3322 ft.
Difference = 37.3322 − 16.3323 ≈ 21.00 ft.
So the foot of the ramp will be about 21.0 feet farther out.
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