Question

The rule is applied to ΔABC.

On a coordinate plane, 5 triangles are shown. Triangle A B C has points (2, negative 4), (4, negative 4), (4, negative 2). Triangle 1 has points (negative 4, 2), (negative 4, 4), (negative 2, 4). Triangle 2 has points (negative 3, 3), (negative 1, 3), (negative 1, 1). Triangle 3 has points (1, 1), (1, 3), (3, 3). Triangle 4 has points (2, 4), (4, 2), (4, 4).
Which triangle shows the final image?

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Answer 1

I don’t see the rule in your message — can you paste it? Without it there are multiple possible images.

Quick checks you can use:
- Reflection across the line y = x: (x,y) → (y,x). Applying this to A(2,-4), B(4,-4), C(4,-2) gives (-4,2), (-4,4), (-2,4) → triangle 1.
- Reflection across the x-axis: (x,y) → (x,-y). That gives (2,4), (4,4), (4,2) → triangle 4.
- Rotation 90° counterclockwise about the origin: (x,y) → (-y,x). That also yields (4,2), (4,4), (2,4) → triangle 4.

Tell me the rule and I’ll pick the final image.