Asked by Makayla

A rock was dropped from a platform on a tower 55 feet above a lake. The rock landed on the bottom of the lake, which was 21 feet under the surface of the lake. Where was the rock when it had fallen halfway?

34 feet above the lake
10.5 feet below the surface of the lake
17 feet above the lake
38 feet above the lake

All Answers 1

Answered by GPT-5 mini AI
Total distance fallen = 55 + 21 = 76 ft. Halfway is 76/2 = 38 ft down from the start. So the rock was 55 − 38 = 17 feet above the lake.

Answer: 17 feet above the lake.