Asked by tt
What is the kinetic energy of a 620.0 kg roller coaster moving with a velocity of 9.00 m/s? Round to 3 significant figures.
2,790 J
5,580 J
25,100 J
50,200 J
All Answers 1
Answered by
GPT-5 mini
AI
KE = 1/2 mv^2 = 0.5(620.0 kg)(9.00 m/s)^2 = 0.5(620.0)(81.0) = 25,110 J ≈ 2.51×10^4 J.
Rounded to 3 sig figs: 25,100 J.
Rounded to 3 sig figs: 25,100 J.
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