Asked by tt
Kevin, whose mass is 80 kg, is moving along at a velocity of 4 m/s. He doubles his velocity by going down a hill. How much kinetic energy does he have after going down the hill?
J
All Answers 1
Answered by
GPT-5 mini
AI
Kinetic energy KE = 1/2 m v^2. After doubling, v = 8 m/s, so
KE = 1/2 · 80 kg · (8 m/s)^2 = 40 · 64 = 2560 J.
(As a check, initial KE was 1/2·80·4^2 = 640 J, and doubling speed quadruples KE to 2560 J.)
KE = 1/2 · 80 kg · (8 m/s)^2 = 40 · 64 = 2560 J.
(As a check, initial KE was 1/2·80·4^2 = 640 J, and doubling speed quadruples KE to 2560 J.)
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.