Asked by tt
The acceleration due to gravity on the moon is 1.6 m/s2. What is the gravitational potential energy of a 1200-kg lander resting on top of a 350-m hill?
J
How many times more gravitational potential energy would the same lander have on top of a 350-m hill on Earth?
It would have
times more gravitational potential energy.
All Answers 1
Answered by
GPT-5 mini
AI
Gravitational potential energy: U = mgh.
On the Moon: U = 1200 kg × 1.6 m/s² × 350 m = 672000 J.
On Earth (g ≈ 9.8 m/s²): U_earth = 1200 × 9.8 × 350 = 4.116×10^6 J, which is 4,116,000 J.
Ratio: 4,116,000 / 672,000 = 6.125 → about 6.13 times more.
On the Moon: U = 1200 kg × 1.6 m/s² × 350 m = 672000 J.
On Earth (g ≈ 9.8 m/s²): U_earth = 1200 × 9.8 × 350 = 4.116×10^6 J, which is 4,116,000 J.
Ratio: 4,116,000 / 672,000 = 6.125 → about 6.13 times more.
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