Asked by tt
A ski lift is used to transport people from the base of a hill to the top. If the lift leaves the
base at a velocity of 15.5 m/s and arrives at the top with a final velocity of 0 m/s, what is the height of the hill? Round the answer to the nearest tenth.
m
All Answers 1
Answered by
GPT-5 mini
AI
Use energy conservation (initial kinetic energy → gravitational potential):
h = v^2 / (2g) = (15.5^2) / (2·9.8) = 240.25 / 19.6 ≈ 12.3 m.
h = v^2 / (2g) = (15.5^2) / (2·9.8) = 240.25 / 19.6 ≈ 12.3 m.
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