Asked by shanease
At the end of each quarter, a 52-year-old individual puts $1300 in a retirement account that pays 9.1% interest compounded quarterly.
(a) When the individual reaches age 60, what is the value of the account?
(b) If no further deposits or withdrawals are made to the account, what is the value of the account when the individual reaches age 65?
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Part 1
(a) When the individual reaches age 60, the value of the account will be $
enter your response here.
(Do not round until the final answer. Then round to the nearest cent as needed.)
(b) When the individual reaches age 65, the value of the account will be $
enter your response here.
(Do not round until the final answer. Then round to the nearest cent as needed.)
All Answers 1
Answered by
GPT-5 mini
AI
Given: deposit R = $1300 each quarter, nominal rate 9.1% compounded quarterly so i = 0.091/4 = 0.02275 per quarter.
(a) From age 52 to 60 is 8 years = 32 quarters. Future value of an ordinary quarterly annuity:
FV60 = R * [((1+i)^n − 1) / i], with n = 32.
Compute (1 + i)^32 ≈ 1.02275^32 ≈ 2.054108832
So FV60 ≈ 1300 * (2.054108832 − 1) / 0.02275
FV60 ≈ 1300 * (1.054108832 / 0.02275) ≈ 1300 * 46.3352999 ≈ $60,235.89
(b) From age 60 to 65 is 5 years = 20 quarters. The balance grows with no deposits:
FV65 = FV60 * (1+i)^{20} = 60,235.89 * 1.02275^{20}
Compute 1.02275^{20} ≈ 1.56815745
FV65 ≈ 60,235.89 * 1.56815745 ≈ $94,459.36
Answers:
(a) $60,235.89
(b) $94,459.36
(a) From age 52 to 60 is 8 years = 32 quarters. Future value of an ordinary quarterly annuity:
FV60 = R * [((1+i)^n − 1) / i], with n = 32.
Compute (1 + i)^32 ≈ 1.02275^32 ≈ 2.054108832
So FV60 ≈ 1300 * (2.054108832 − 1) / 0.02275
FV60 ≈ 1300 * (1.054108832 / 0.02275) ≈ 1300 * 46.3352999 ≈ $60,235.89
(b) From age 60 to 65 is 5 years = 20 quarters. The balance grows with no deposits:
FV65 = FV60 * (1+i)^{20} = 60,235.89 * 1.02275^{20}
Compute 1.02275^{20} ≈ 1.56815745
FV65 ≈ 60,235.89 * 1.56815745 ≈ $94,459.36
Answers:
(a) $60,235.89
(b) $94,459.36
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