Question

Point upper A has coordinates left parenthesis negative 2 comma negative 5 right parenthesis. Point upper B has coordinates left parenthesis 0 comma 3 right parenthesis. Point upper C has coordinates left parenthesis 6 comma negative 3 right parenthesis.

A triangle is drawn on a coordinate plane. Dilate the figure with a magnitude of 3 in reference to the origin. What are the coordinates of the new vertices of A′B′C′
𝐴
′
𝐵
′
𝐶
′
?

(1 point)
Responses

A′(1,−2)
𝐴
′
(
1
,
−
2
)
, B′(3,6)
𝐵
′
(
3
,
6
)
, and C′(9,0)
𝐶
′
(
9
,
0
)

upper A prime left parenthesis 1 comma negative 2 right parenthesis , upper B prime left parenthesis 3 comma 6 right parenthesis , and upper C prime left parenthesis 9 comma 0 right parenthesis

A′(−5,−8)
𝐴
′
(
−
5
,
−
8
)
, B′(−3,0)
𝐵
′
(
−
3
,
0
)
, and C′(3,0)
𝐶
′
(
3
,
0
)

upper A prime left parenthesis negative 5 comma negative 8 right

Answer 1

Multiply each coordinate by 3 (dilation about the origin).

A' = 3(−2, −5) = (−6, −15)
B' = 3(0, 3) = (0, 9)
C' = 3(6, −3) = (18, −9)