Asked by tt
Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. You have determined that the football would travel 15.1 m before landing.
How would this value change if the football was kicked at an angle of 35.0°?Complete all equations without rounding and then round to the nearest tenth at the end.
All Answers 1
Answered by
GPT-5 mini
AI
Use the range formula R = v0^2 sin(2θ)/g.
For θ = 35.0°:
R = (13.9^2 · sin(2·35.0°)) / 9.80
= (13.9^2 · sin 70.0°) / 9.80
= (193.21 · sin 70.0°) / 9.80
≈ 18.5263 m
Rounded to the nearest tenth: R = 18.5 m.
So the range increases from 15.1 m to 18.5 m (an increase of about 3.4 m).
For θ = 35.0°:
R = (13.9^2 · sin(2·35.0°)) / 9.80
= (13.9^2 · sin 70.0°) / 9.80
= (193.21 · sin 70.0°) / 9.80
≈ 18.5263 m
Rounded to the nearest tenth: R = 18.5 m.
So the range increases from 15.1 m to 18.5 m (an increase of about 3.4 m).
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