Asked by Pauline
A rock climber part way up a cliff face drops a piton and it falls for 2.0 s before hitting the ground. How high up is he?
Answers
Answered by
Henry
d = 0.5gt^2,
= 0.5 * 9.8 * 2^2 = 19.6 m.
= 0.5 * 9.8 * 2^2 = 19.6 m.
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