Question

What is the domain of the square root function graphed below?

On a coordinate plane, a curve open up to the right in quadrant 4. It starts at (0, negative 1) and goes through (1, negative 2) and (4, negative 3).
x less-than-or-equal-to negative 1
x greater-than-or-equal-to negative 1
x less-than-or-equal-to 0

Answer 1

The left endpoint of the curve is at x = 0 and it extends to the right, so the domain is all x ≥ 0. (For example the graph fits y = −1 − √x, which gives y(0)=−1, y(1)=−2, y(4)=−3.)

None of the three choices listed (x ≤ −1, x ≥ −1, x ≤ 0) is correct.