Question

A stretched spring has 5184 J of elastic potential energy and a spring constant of 16,200 N/m. What is the displacement of the spring?

0.57 m
0.64 m
0.80 m
1.25 m

Answer 1

Use U = 1/2 k x^2 → x = sqrt(2U/k).

x = sqrt(2·5184 / 16200) = sqrt(10368/16200) = sqrt(0.64) = 0.80 m.

Answer: 0.80 m.