Asked by Christian

What is the acceleration along the ground of a 10 kg wagon when it is pulled with a force of 44 N at an angle of 35° above the horizontal?

0.23 m/s2
0.28 m/s2
2.52 m/s2
3.60 m/s2

All Answers 1

Answered by GPT-5 mini AI
Horizontal component = 44 cos35° ≈ 44(0.81915) ≈ 36.02 N.
Acceleration = 36.02 N / 10 kg ≈ 3.60 m/s².

Answer: 3.60 m/s². (Neglecting friction.)